Optimal. Leaf size=124 \[ -\frac {\left (a+b \tan ^{-1}\left (c x^3\right )\right )^2}{12 c^4}+\frac {a b x^3}{6 c^3}+\frac {1}{12} x^{12} \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2-\frac {b x^9 \left (a+b \tan ^{-1}\left (c x^3\right )\right )}{18 c}+\frac {b^2 x^3 \tan ^{-1}\left (c x^3\right )}{6 c^3}+\frac {b^2 x^6}{36 c^2}-\frac {b^2 \log \left (c^2 x^6+1\right )}{9 c^4} \]
[Out]
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Rubi [C] time = 1.65, antiderivative size = 731, normalized size of antiderivative = 5.90, number of steps used = 62, number of rules used = 19, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.187, Rules used = {5035, 2454, 2398, 2411, 43, 2334, 12, 14, 2301, 2395, 2439, 2416, 2389, 2295, 2394, 2393, 2391, 2410, 2390} \[ -\frac {b^2 \text {PolyLog}\left (2,\frac {1}{2} \left (1-i c x^3\right )\right )}{24 c^4}-\frac {b^2 \text {PolyLog}\left (2,\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}+\frac {a b x^3}{12 c^3}-\frac {b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{48 c^2}+\frac {1}{288} i b \left (-\frac {3 \left (1-i c x^3\right )^4}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )+\frac {b \log \left (\frac {1}{2} \left (1+i c x^3\right )\right ) \left (2 i a-b \log \left (1-i c x^3\right )\right )}{24 c^4}+\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{96} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right )-\frac {1}{24} b x^{12} \log \left (1+i c x^3\right ) \left (2 i a-b \log \left (1-i c x^3\right )\right )+\frac {i b x^9 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{72 c}+\frac {b^2 x^6}{192 c^2}-\frac {23 i b^2 x^3}{288 c^3}-\frac {b^2 \left (1-i c x^3\right )^4}{384 c^4}+\frac {b^2 \left (1-i c x^3\right )^3}{54 c^4}-\frac {b^2 \left (1-i c x^3\right )^2}{16 c^4}-\frac {b^2 \log ^2\left (1-i c x^3\right )}{48 c^4}+\frac {b^2 \log ^2\left (1+i c x^3\right )}{48 c^4}-\frac {b^2 \log \left (-c x^3+i\right )}{36 c^4}-\frac {b^2 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{24 c^4}-\frac {b^2 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{12 c^4}-\frac {b^2 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{24 c^4}+\frac {5 b^2 \log \left (c x^3+i\right )}{288 c^4}-\frac {7 i b^2 x^9}{864 c}-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )+\frac {i b^2 x^9 \log \left (1+i c x^3\right )}{36 c}+\frac {b^2 x^{12}}{384} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
Rule 12
Rule 14
Rule 43
Rule 2295
Rule 2301
Rule 2334
Rule 2389
Rule 2390
Rule 2391
Rule 2393
Rule 2394
Rule 2395
Rule 2398
Rule 2410
Rule 2411
Rule 2416
Rule 2439
Rule 2454
Rule 5035
Rubi steps
\begin {align*} \int x^{11} \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2 \, dx &=\int \left (\frac {1}{4} x^{11} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{2} b x^{11} \left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )-\frac {1}{4} b^2 x^{11} \log ^2\left (1+i c x^3\right )\right ) \, dx\\ &=\frac {1}{4} \int x^{11} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \, dx+\frac {1}{2} b \int x^{11} \left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right ) \, dx-\frac {1}{4} b^2 \int x^{11} \log ^2\left (1+i c x^3\right ) \, dx\\ &=\frac {1}{12} \operatorname {Subst}\left (\int x^3 (2 a+i b \log (1-i c x))^2 \, dx,x,x^3\right )+\frac {1}{6} b \operatorname {Subst}\left (\int x^3 (-2 i a+b \log (1-i c x)) \log (1+i c x) \, dx,x,x^3\right )-\frac {1}{12} b^2 \operatorname {Subst}\left (\int x^3 \log ^2(1+i c x) \, dx,x,x^3\right )\\ &=\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )-\frac {1}{24} (i b c) \operatorname {Subst}\left (\int \frac {x^4 (-2 i a+b \log (1-i c x))}{1+i c x} \, dx,x,x^3\right )-\frac {1}{24} (b c) \operatorname {Subst}\left (\int \frac {x^4 (2 a+i b \log (1-i c x))}{1-i c x} \, dx,x,x^3\right )+\frac {1}{24} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4 \log (1+i c x)}{1-i c x} \, dx,x,x^3\right )+\frac {1}{24} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4 \log (1+i c x)}{1+i c x} \, dx,x,x^3\right )\\ &=\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )-\frac {1}{24} (i b) \operatorname {Subst}\left (\int \frac {\left (-\frac {i}{c}+\frac {i x}{c}\right )^4 (2 a+i b \log (x))}{x} \, dx,x,1-i c x^3\right )-\frac {1}{24} (i b c) \operatorname {Subst}\left (\int \left (-\frac {-2 i a+b \log (1-i c x)}{c^4}+\frac {i x (-2 i a+b \log (1-i c x))}{c^3}+\frac {x^2 (-2 i a+b \log (1-i c x))}{c^2}-\frac {i x^3 (-2 i a+b \log (1-i c x))}{c}-\frac {i (-2 i a+b \log (1-i c x))}{c^4 (-i+c x)}\right ) \, dx,x,x^3\right )+\frac {1}{24} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {\log (1+i c x)}{c^4}+\frac {i x \log (1+i c x)}{c^3}+\frac {x^2 \log (1+i c x)}{c^2}-\frac {i x^3 \log (1+i c x)}{c}-\frac {i \log (1+i c x)}{c^4 (-i+c x)}\right ) \, dx,x,x^3\right )+\frac {1}{24} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {\log (1+i c x)}{c^4}-\frac {i x \log (1+i c x)}{c^3}+\frac {x^2 \log (1+i c x)}{c^2}+\frac {i x^3 \log (1+i c x)}{c}+\frac {i \log (1+i c x)}{c^4 (i+c x)}\right ) \, dx,x,x^3\right )\\ &=\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{288} i b \left (2 a+i b \log \left (1-i c x^3\right )\right ) \left (\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {3 \left (1-i c x^3\right )^4}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right )-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )-\frac {1}{24} b \operatorname {Subst}\left (\int x^3 (-2 i a+b \log (1-i c x)) \, dx,x,x^3\right )-\frac {1}{24} b^2 \operatorname {Subst}\left (\int \frac {x \left (-48+36 x-16 x^2+3 x^3\right )+12 \log (x)}{12 c^4 x} \, dx,x,1-i c x^3\right )+\frac {(i b) \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x)) \, dx,x,x^3\right )}{24 c^3}-\frac {b \operatorname {Subst}\left (\int \frac {-2 i a+b \log (1-i c x)}{-i+c x} \, dx,x,x^3\right )}{24 c^3}-2 \frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \log (1+i c x) \, dx,x,x^3\right )}{24 c^3}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (1+i c x)}{-i+c x} \, dx,x,x^3\right )}{24 c^3}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (1+i c x)}{i+c x} \, dx,x,x^3\right )}{24 c^3}+\frac {b \operatorname {Subst}\left (\int x (-2 i a+b \log (1-i c x)) \, dx,x,x^3\right )}{24 c^2}-\frac {(i b) \operatorname {Subst}\left (\int x^2 (-2 i a+b \log (1-i c x)) \, dx,x,x^3\right )}{24 c}+2 \frac {\left (i b^2\right ) \operatorname {Subst}\left (\int x^2 \log (1+i c x) \, dx,x,x^3\right )}{24 c}\\ &=\frac {a b x^3}{12 c^3}-\frac {b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{48 c^2}+\frac {i b x^9 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{72 c}+\frac {1}{96} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right )+\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{288} i b \left (2 a+i b \log \left (1-i c x^3\right )\right ) \left (\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {3 \left (1-i c x^3\right )^4}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right )+\frac {b \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}-\frac {b^2 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{24 c^4}-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )+\frac {1}{72} b^2 \operatorname {Subst}\left (\int \frac {x^3}{1-i c x} \, dx,x,x^3\right )+2 \left (\frac {i b^2 x^9 \log \left (1+i c x^3\right )}{72 c}+\frac {1}{72} b^2 \operatorname {Subst}\left (\int \frac {x^3}{1+i c x} \, dx,x,x^3\right )\right )-\frac {b^2 \operatorname {Subst}\left (\int \frac {x \left (-48+36 x-16 x^2+3 x^3\right )+12 \log (x)}{x} \, dx,x,1-i c x^3\right )}{288 c^4}-2 \frac {b^2 \operatorname {Subst}\left (\int \log (x) \, dx,x,1+i c x^3\right )}{24 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1+i c x^3\right )}{24 c^4}+\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \log (1-i c x) \, dx,x,x^3\right )}{24 c^3}-\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} i (-i+c x)\right )}{1-i c x} \, dx,x,x^3\right )}{24 c^3}+\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {1}{2} i (i+c x)\right )}{1+i c x} \, dx,x,x^3\right )}{24 c^3}+\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \frac {x^2}{1-i c x} \, dx,x,x^3\right )}{48 c}-\frac {1}{96} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^4}{1-i c x} \, dx,x,x^3\right )\\ &=\frac {a b x^3}{12 c^3}-\frac {b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{48 c^2}+\frac {i b x^9 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{72 c}+\frac {1}{96} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right )+\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{288} i b \left (2 a+i b \log \left (1-i c x^3\right )\right ) \left (\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {3 \left (1-i c x^3\right )^4}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right )+\frac {b \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}-\frac {b^2 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{24 c^4}-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )+\frac {b^2 \log ^2\left (1+i c x^3\right )}{48 c^4}-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )-2 \left (-\frac {i b^2 x^3}{24 c^3}+\frac {b^2 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{24 c^4}\right )+2 \left (\frac {i b^2 x^9 \log \left (1+i c x^3\right )}{72 c}+\frac {1}{72} b^2 \operatorname {Subst}\left (\int \left (\frac {i}{c^3}+\frac {x}{c^2}-\frac {i x^2}{c}-\frac {1}{c^3 (-i+c x)}\right ) \, dx,x,x^3\right )\right )+\frac {1}{72} b^2 \operatorname {Subst}\left (\int \left (-\frac {i}{c^3}+\frac {x}{c^2}+\frac {i x^2}{c}-\frac {1}{c^3 (i+c x)}\right ) \, dx,x,x^3\right )-\frac {b^2 \operatorname {Subst}\left (\int \left (-48+36 x-16 x^2+3 x^3+\frac {12 \log (x)}{x}\right ) \, dx,x,1-i c x^3\right )}{288 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1-i c x^3\right )}{24 c^4}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1+i c x^3\right )}{24 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \log (x) \, dx,x,1-i c x^3\right )}{24 c^4}+\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \left (\frac {1}{c^2}+\frac {i x}{c}-\frac {i}{c^2 (i+c x)}\right ) \, dx,x,x^3\right )}{48 c}-\frac {1}{96} \left (i b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {1}{c^4}-\frac {i x}{c^3}+\frac {x^2}{c^2}+\frac {i x^3}{c}+\frac {i}{c^4 (i+c x)}\right ) \, dx,x,x^3\right )\\ &=\frac {a b x^3}{12 c^3}-\frac {55 i b^2 x^3}{288 c^3}-\frac {5 b^2 x^6}{576 c^2}+\frac {i b^2 x^9}{864 c}+\frac {b^2 x^{12}}{384}-\frac {b^2 \left (1-i c x^3\right )^2}{16 c^4}+\frac {b^2 \left (1-i c x^3\right )^3}{54 c^4}-\frac {b^2 \left (1-i c x^3\right )^4}{384 c^4}-\frac {b^2 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{24 c^4}-\frac {b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{48 c^2}+\frac {i b x^9 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{72 c}+\frac {1}{96} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right )+\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{288} i b \left (2 a+i b \log \left (1-i c x^3\right )\right ) \left (\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {3 \left (1-i c x^3\right )^4}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right )+\frac {b \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}-\frac {b^2 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{24 c^4}-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )+\frac {b^2 \log ^2\left (1+i c x^3\right )}{48 c^4}-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )+2 \left (\frac {i b^2 x^3}{72 c^3}+\frac {b^2 x^6}{144 c^2}-\frac {i b^2 x^9}{216 c}-\frac {b^2 \log \left (i-c x^3\right )}{72 c^4}+\frac {i b^2 x^9 \log \left (1+i c x^3\right )}{72 c}\right )-2 \left (-\frac {i b^2 x^3}{24 c^3}+\frac {b^2 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{24 c^4}\right )+\frac {5 b^2 \log \left (i+c x^3\right )}{288 c^4}-\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{24 c^4}-\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}-\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (x)}{x} \, dx,x,1-i c x^3\right )}{24 c^4}\\ &=\frac {a b x^3}{12 c^3}-\frac {55 i b^2 x^3}{288 c^3}-\frac {5 b^2 x^6}{576 c^2}+\frac {i b^2 x^9}{864 c}+\frac {b^2 x^{12}}{384}-\frac {b^2 \left (1-i c x^3\right )^2}{16 c^4}+\frac {b^2 \left (1-i c x^3\right )^3}{54 c^4}-\frac {b^2 \left (1-i c x^3\right )^4}{384 c^4}-\frac {b^2 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{24 c^4}-\frac {b^2 \log ^2\left (1-i c x^3\right )}{48 c^4}-\frac {b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{48 c^2}+\frac {i b x^9 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{72 c}+\frac {1}{96} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right )+\frac {1}{48} x^{12} \left (2 a+i b \log \left (1-i c x^3\right )\right )^2+\frac {1}{288} i b \left (2 a+i b \log \left (1-i c x^3\right )\right ) \left (\frac {48 \left (1-i c x^3\right )}{c^4}-\frac {36 \left (1-i c x^3\right )^2}{c^4}+\frac {16 \left (1-i c x^3\right )^3}{c^4}-\frac {3 \left (1-i c x^3\right )^4}{c^4}-\frac {12 \log \left (1-i c x^3\right )}{c^4}\right )+\frac {b \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}-\frac {b^2 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{24 c^4}-\frac {1}{24} b x^{12} \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )+\frac {b^2 \log ^2\left (1+i c x^3\right )}{48 c^4}-\frac {1}{48} b^2 x^{12} \log ^2\left (1+i c x^3\right )+2 \left (\frac {i b^2 x^3}{72 c^3}+\frac {b^2 x^6}{144 c^2}-\frac {i b^2 x^9}{216 c}-\frac {b^2 \log \left (i-c x^3\right )}{72 c^4}+\frac {i b^2 x^9 \log \left (1+i c x^3\right )}{72 c}\right )-2 \left (-\frac {i b^2 x^3}{24 c^3}+\frac {b^2 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{24 c^4}\right )+\frac {5 b^2 \log \left (i+c x^3\right )}{288 c^4}-\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{24 c^4}-\frac {b^2 \text {Li}_2\left (\frac {1}{2} \left (1+i c x^3\right )\right )}{24 c^4}\\ \end {align*}
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Mathematica [A] time = 0.10, size = 121, normalized size = 0.98 \[ \frac {c x^3 \left (3 a^2 c^3 x^9-2 a b c^2 x^6+6 a b+b^2 c x^3\right )-2 b \tan ^{-1}\left (c x^3\right ) \left (a \left (3-3 c^4 x^{12}\right )+b c x^3 \left (c^2 x^6-3\right )\right )+3 b^2 \left (c^4 x^{12}-1\right ) \tan ^{-1}\left (c x^3\right )^2-4 b^2 \log \left (c^2 x^6+1\right )}{36 c^4} \]
Antiderivative was successfully verified.
[In]
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fricas [A] time = 0.47, size = 129, normalized size = 1.04 \[ \frac {3 \, a^{2} c^{4} x^{12} - 2 \, a b c^{3} x^{9} + b^{2} c^{2} x^{6} + 6 \, a b c x^{3} + 3 \, {\left (b^{2} c^{4} x^{12} - b^{2}\right )} \arctan \left (c x^{3}\right )^{2} - 4 \, b^{2} \log \left (c^{2} x^{6} + 1\right ) + 2 \, {\left (3 \, a b c^{4} x^{12} - b^{2} c^{3} x^{9} + 3 \, b^{2} c x^{3} - 3 \, a b\right )} \arctan \left (c x^{3}\right )}{36 \, c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.19, size = 145, normalized size = 1.17 \[ \frac {3 \, a^{2} c x^{12} + 2 \, {\left (3 \, c x^{12} \arctan \left (c x^{3}\right ) - \frac {3 \, \arctan \left (c x^{3}\right )}{c^{3}} - \frac {c^{9} x^{9} - 3 \, c^{7} x^{3}}{c^{9}}\right )} a b + {\left (3 \, c x^{12} \arctan \left (c x^{3}\right )^{2} - \frac {2 \, c^{3} x^{9} \arctan \left (c x^{3}\right ) - c^{2} x^{6} - 6 \, c x^{3} \arctan \left (c x^{3}\right ) + 3 \, \arctan \left (c x^{3}\right )^{2} + 4 \, \log \left (c^{2} x^{6} + 1\right )}{c^{3}}\right )} b^{2}}{36 \, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 151, normalized size = 1.22 \[ \frac {x^{12} a^{2}}{12}+\frac {b^{2} x^{12} \arctan \left (c \,x^{3}\right )^{2}}{12}-\frac {b^{2} \arctan \left (c \,x^{3}\right ) x^{9}}{18 c}+\frac {b^{2} x^{3} \arctan \left (c \,x^{3}\right )}{6 c^{3}}-\frac {b^{2} \arctan \left (c \,x^{3}\right )^{2}}{12 c^{4}}+\frac {b^{2} x^{6}}{36 c^{2}}-\frac {b^{2} \ln \left (c^{2} x^{6}+1\right )}{9 c^{4}}+\frac {a b \,x^{12} \arctan \left (c \,x^{3}\right )}{6}-\frac {a b \,x^{9}}{18 c}+\frac {a b \,x^{3}}{6 c^{3}}-\frac {a b \arctan \left (c \,x^{3}\right )}{6 c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.52, size = 169, normalized size = 1.36 \[ \frac {1}{12} \, b^{2} x^{12} \arctan \left (c x^{3}\right )^{2} + \frac {1}{12} \, a^{2} x^{12} + \frac {1}{18} \, {\left (3 \, x^{12} \arctan \left (c x^{3}\right ) - c {\left (\frac {c^{2} x^{9} - 3 \, x^{3}}{c^{4}} + \frac {3 \, \arctan \left (c x^{3}\right )}{c^{5}}\right )}\right )} a b - \frac {1}{36} \, {\left (2 \, c {\left (\frac {c^{2} x^{9} - 3 \, x^{3}}{c^{4}} + \frac {3 \, \arctan \left (c x^{3}\right )}{c^{5}}\right )} \arctan \left (c x^{3}\right ) - \frac {c^{2} x^{6} + 3 \, \arctan \left (c x^{3}\right )^{2} - 3 \, \log \left (18 \, c^{7} x^{6} + 18 \, c^{5}\right ) - \log \left (c^{2} x^{6} + 1\right )}{c^{4}}\right )} b^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.14, size = 150, normalized size = 1.21 \[ \frac {a^2\,x^{12}}{12}-\frac {b^2\,{\mathrm {atan}\left (c\,x^3\right )}^2}{12\,c^4}+\frac {b^2\,x^{12}\,{\mathrm {atan}\left (c\,x^3\right )}^2}{12}-\frac {b^2\,\ln \left (c^2\,x^6+1\right )}{9\,c^4}+\frac {b^2\,x^6}{36\,c^2}+\frac {b^2\,x^3\,\mathrm {atan}\left (c\,x^3\right )}{6\,c^3}-\frac {b^2\,x^9\,\mathrm {atan}\left (c\,x^3\right )}{18\,c}+\frac {a\,b\,x^3}{6\,c^3}-\frac {a\,b\,x^9}{18\,c}-\frac {a\,b\,\mathrm {atan}\left (c\,x^3\right )}{6\,c^4}+\frac {a\,b\,x^{12}\,\mathrm {atan}\left (c\,x^3\right )}{6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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